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Water jugs: calculate the space left

Track two quantities at once and calculate how much can move between containers without markings.

By Piko Game · Updated

Before you start

You need subtraction with small whole numbers. Treat this as a paper puzzle; no water equipment is required.

Work through this example

Jug A holds 3 L and B holds 5 L. Both start empty. You may fill a jug, empty it or pour into the other until the source is empty or the receiver is full. Leave 4 L in B within six operations.

A: 3 L · B: 5 L
OperationA (L)B (L)
Start00
1. Fill B05
2. Pour B into A32
3. Empty A02
4. Pour B into A20
5. Fill B25
6. Pour B into A34

Reason step by step

  1. Fill B, then pour B into A. A can take 3 L, leaving the state (A,B) = (3,2).
  2. Empty A, then move B’s remaining 2 L into A. Now (A,B) = (2,0). Filling B again gives (2,5).
  3. A has room for only 3 − 2 = 1 L. Pouring from B transfers 1 L, leaving (3,4). The target is reached after six operations.

A mistake worth understanding

Do not subtract A’s full capacity every time. In the last pour A is not empty. The amount transferred is min(source water, free receiving space).

Try it yourself

Restart with empty jugs. How can you leave exactly 2 L in B using two operations? Why can you not simply stop pouring B after 1 L without using A?

Show the answer and reasoning

Fill B and pour into empty A: (0,5) → (3,2). Without markings, an arbitrary 1 L stopping point is not an allowed operation.

Use the idea in the game

In the game, read both capacities and the target again. Reaching the target in either jug counts; the six-step sequence here applies to this example, not every generated puzzle.

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About & help

These examples were written for Piko Game. Generated game questions may differ. A score describes a game attempt, not mastery of a school curriculum.

Content and corrections

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